Answer:
is outside the circle of radius of
centered at
.
Step-by-step explanation:
Let
and
denote the center and the radius of this circle, respectively. Let
be a point in the plane.
Let
denote the Euclidean distance between point
and point
.
In other words, if
is at
while
is at
, then
.
Point
would be inside this circle if
. (In other words, the distance between
and the center of this circle is smaller than the radius of this circle.)
Point
would be on this circle if
. (In other words, the distance between
and the center of this circle is exactly equal to the radius of this circle.)
Point
would be outside this circle if
. (In other words, the distance between
and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between
and
:
.
On the other hand, notice that the radius of this circle,
, is smaller than
. Therefore, point
would be outside this circle.
Answer:
90
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
-3x(4x-2)
-3*-8
+24
-*-=+
+*-=-
-*+=-
Here, we are required to find the vertical and horizontal intercepts for r⁴ + s² − r s = 16.
The vertical and horizontal intercepts are s = ±4 and r = ±2 respectively.
According to the question;
- the r-axis is the horizontal axis.
- the s-axis is the vertical axis.
Therefore, to get the horizontal intercepts, r we set the vertical axis, s to zero(0).
- i.e s = 0
- the equation r⁴ + s² − r s = 16, then becomes;
- r⁴ = 16
- Therefore, r = ±2.
Also, to to get the vertical intercepts, s we set the horizontal axis, r to zero(0).
- i.e r = 0.
- the equation r⁴ + s² − r s = 16, then becomes;
- s² = 16.
- Therefore, s = ±4.
Therefore, the vertical and horizontal intercepts are s = ±4 and r = ±2 respectively.
Read more:
brainly.com/question/18466425
The answer is C, one over thirty-two