HELP ASAP WITH THIS PLEASE MATH

Oksi-84 [34.3K]

Would the common factor be 1?
edit
the least common is 1 and the most common is 2

thanks andreadiaz2003

6 0

3 years ago

The distance light travels in one year is known as a light year. A light year is equal to 5.87 × 1012 miles. The closest that Ea

pashok25 [27]

Answer:

$6.21\times 10^{-5}\ \text{light years}$

Step-by-step explanation:

The distance light travels in one year is known as a light year.

$1\ \text{light year}=5.87\times 10^{12}\ \text{miles}$

The closest that Earth ever gets to Jupiter is $3.65\times 10^8\ \text{miles}$

$3.65\times 10^8\ \text{miles}=\dfrac{1}{5.87\times 10^{12}}\times 3.65\times 10^8\ \text{light years}\\\\=6.21\times 10^{-5}\ \text{light years}$

Hence, the distance it will take light to travel from Earth to Jupiter at this distance is $6.21\times 10^{-5}\ \text{light years}$

4 0

2 years ago

Rewrite the following polynomial in standard form. -x -7x^2 -10<br><br> Please Help

DIA [1.3K]

Answer:

-7x^2 - x - 10

Step-by-step explanation:

Rewriting a polynomial in standard form most often involves writing the x terms in descending order by power: x^2, x^1, x^0

Rewrite -x -7x^2 -10 as -7x^2 - x^1 - 10x^0, which is usually simplified to:

-7x^2 - x - 10

This result is in "standard form."

7 0

2 years ago

Read 2 more answers

the length of a rectangle is 7 inches greater than three times its width write an expression to represent its area

icang [17]

Step-by-step explanation:

Let the length be L.

Let the breath be B.

So, we are given that

length of a rectangle is 7 inches greater than three times its width .

So, according to the Question,

L = 7+ 3B.

So, we know that:-

Area = Length× Breadth.

So, it will be

B × (7 + 3B) = Area.

So,

3B² + 7 is an expression to represent its area.

3 0

3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

3 years ago