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Anni [7]
3 years ago
6

The Punnett Square shows a cross between a mouse with black fur whose genetic makeup was BB, and a mouse with white fur whose ge

netic makeup was bb.
Explain why all of the offspring have black fur, even though each of them has a gene for white fur?

Biology
2 answers:
NNADVOKAT [17]3 years ago
7 0

Answer:

There must have two white genes to become white.

Explanation:

In order to a mouse to have white fur, both of their genes must be white. In the punnet square, you have a Black (BB) and a white (bb). If they have offspring, all of them have one black (Dominant) and one white (recessive). The black gene overpowers the white gene, so they come out black.

devlian [24]3 years ago
3 0
White is recessive so there must be 2 white mice to great a white mouse
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Answer:

Sample A

T= 21.3% and A= 21.3%

G=28.7% and C= 28.7%

SAMPLE B

T=28.7% and  A= 28.7%

G= 21.3% and C= 21.3%

Sample A would have higher melting temperature

Explanation:

According to given information, sample A contains 21.3% thymine.

Percentage of adenine in sample A= 21.3% (Since adenine base pairs with thymine, so, adenine and thymine are present in equal amount in a double stranded DNA)

Total of A+T in sample A= 21.3 + 21.3 = 42.6%

G+ C content of sample A= 100-42.6= 57.4%

Percent G content of sample A = 57.4/2 = 28.7%

Percent C content of sample A = 28.7%

SAMPLE B:

According to the given information, sample B contains 28.7% thymine.

Therefore, percent of Adenine base in sample B= 28.7%

Total of A+T content in sample B= 28.7 + 28.7 = 57.4%

G + C content of the sample B = 100-57.4= 42.6%

Percent G content of the sample B= 42.6/2= 21.3%

Percent C content of sample B = 21.3%

There are three hydrogen bonds between a GC pair while there are only two hydrogen bonds between AT pair. The DNA content with higher GC content has higher melting temperature. Therefore, sample A would have higher melting temperature.

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3 years ago
Maintaining the integrity of the stock reagents is a constant concern in the lab environment. Read the situations and decide if
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Answer:

Question is incomplete i have added full question at the end of this answer because im not able to add it in ask for detail section.

Answer:

1. Contaminate (Because NaOH is a base while H2SO4 is an acid. If student mix both this will result in chemical reaction.)

2. Contaminate (Because returning regents  are used already id used regents put back in the bottle it will contaminate the fresh reagents.)

3. Contaminate (Using same spatula without sanitation results in mixing of one reagent into other regents which results in failure of experiments.)

4. Does Not Contaminate (It does not have any effect on the reagent because solid reagents are weighted that can be cleaned off when poured into reaction flask.)

5. Does Not Contaminate (Because washing flask after each experiment will wash off the left reagents present in flask.)

6. Contaminate (This will result in contamination because potassium iodide (KI) solution will be mixed with waste)

FULL QUESTION

Maintaining the integrity of the stock reagents is a constant concern in the lab environment. Read the following situations and decide if each represents a valid contamination concern.

1. A student uses a pipet designated for the NaOH solution to pipet the H2SO4 solution.

2. Several students have left-over reagents after the completion of an experiment and decide to return the excess reagents to their original containers.

3. Only one spatula is available to measure out several different white powders.

4.Rather than wasting multiple weigh boats, a student decides to wash and dry a single weigh boat in-between uses.

5. A group of students must use the same 500 mL volumetric flask to make solutions. Between each use they wash and dry the flask.

6. At the end of the day, the waste bottle is so full that a student decides to dump his waste into an almost empty bottle of stock KI solution.

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