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Vera_Pavlovna [14]
3 years ago
8

Which logarithmic equation is equivalent to 2^5=32?

Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0

Answer: 5=log_{2}(32)


Step-by-step explanation:

1. By definition, you have if y=b^{x}, then x=log_{b}(y)

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

2^{5}=32

Where:

x=5\\y=32\\b=2

- Substitute values into x=log_{b}(y). Then, you obtain:

5=log_{2}(32)


marysya [2.9K]3 years ago
3 0

Answer:

5 = log₂ 32

Step-by-step explanation:

When a logarithmic equation is written as b = logₐ c

That means its exponential form is aᵇ = c

In this question exponential expression is given as 2⁵ = 32

By comparing with exponential form given above we find a = 2, b = 5 and c = 32

Now we put these values in the logarithmic equation

5 = log₂ 32 will be the logarithmic equation.

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