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vlada-n [284]
3 years ago
6

If the radius of a sphere is increased by 5 cm so that the area of the sphere obtained is increased by 400pi square cm. What was

the radius before the increase
Mathematics
1 answer:
Sliva [168]3 years ago
8 0

Answer:

The answer is 314cm²

the formula for the sphere area of a sphere is:

A= 4TT²

A = 4x3.14x5²

first solve for exponents

A = 4x 3.14x25

then multiply

A = 314cm²

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now when we add tan</span>θ and cot<span>θ and replace their values;

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Step-by-step explanation:

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Ksenya-84 [330]

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Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as
stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

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c^{2}=a^{2}+b^{2}

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In this problem

Let

a=7\ cm\\c=13\ cm

substitute

13^{2}=7^{2}+b^{2}

Solve for b

169=49+b^{2}

b^{2}=169-49

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b=\sqrt{120}\ cm

b=10.95\ cm

we have that

<em>Jayden's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\b=13\ cm

substitute and solve for c

7^{2}+13^{2}=c^{2}

49+169=c^{2}

218=c^{2}

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Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\c=13\ cm

substitute

7^{2}+b^{2}=13^{2}

Solve for b

49+b^{2}=169

b^{2}=169-49

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b=10.95\ cm

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