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2 years ago

6

If the radius of a sphere is increased by 5 cm so that the area of the sphere obtained is increased by 400pi square cm. What was

the radius before the increase

1 answer:

Sliva [168]2 years ago

8 0

Answer:

The answer is 314cm²

the formula for the sphere area of a sphere is:

A= 4TT²

A = 4x3.14x5²

first solve for exponents

A = 4x 3.14x25

then multiply

A = 314cm²

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PLEASE HELP ME <br>Multiply the monomials: <br><br>a2x5b, −0.6axb2 and 0.6a2b3

Tanzania [10]

Answer:

$-0.36 a^{5}b^{6} x^{6}$

Step-by-step explanation:

Given:

$a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3$

Required

Multiply

The above can be written as

$a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$

Split the above expression

$a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3$

Collect like terms

$-0.6 * 0.6 * a^2*a*a^2*b *b^2 *b^3*x^5*x$

Apply first law on indices

$-0.36 * a^{2+1+2} *b^{1+2+3} *x^{5+1}$

$-0.36 * a^{5} *b^{6} *x^{6}$

$-0.36 a^{5}b^{6} x^{6}$

Hence, $a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$ is equivalent to $-0.36 a^{5}b^{6} x^{6}$

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~

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