Tanθ + cotθ = 1/sinθcos<span>θ
since we know that;
tan</span>θ = sinθ/cos<span>θ, and
cot</span>θ = cosθ/sin<span>θ
now when we add tan</span>θ and cot<span>θ and replace their values;
tan</span>θ + cot<span>θ=sin</span>θ/cosθ + cosθ/sin<span>θ
</span>For a common denominator to add those two fractions, the obvious choice is sinθ.cosθ , so
tanθ + cotθ = sin²θ/sinθcosθ + cos²θ/sinθcosθ =sin²θ + cos²θ / sinθcosθ
now we can use the identity that;
sin²θ + cos²θ = 1
So,
tanθ + cotθ = 1/sinθcosθ
Answer:
2-packs of candy bars for 0.38 is better to buy
Step-by-step explanation:
Answer:
80000 cm cubed
Step-by-step explanation:
L*W*H
100*20*20
Answer:
Sheridan's Work is correct
Step-by-step explanation:
we know that
The lengths side of a right triangle must satisfy the Pythagoras Theorem

where
a and b are the legs
c is the hypotenuse (the greater side)
In this problem
Let

substitute

Solve for b





we have that
<em>Jayden's Work</em>


substitute and solve for c





Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle
<em>Sheridan's Work</em>


substitute

Solve for b





therefore
Sheridan's Work is correct