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brilliants [131]
4 years ago
13

Write 506.137 in expanded form

Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
5 0
You can get the answer to this on google
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Wht do I put?? Can some one help pls
Contact [7]

Answer:

a=6,

b=4

c=2.

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Can someone help this is due in like 20 minutes Find the value of x in the triangle shown below. 58° 6 6 5.8 ​
SpyIntel [72]

Answer:

I'm wonde what it is because I like this stuff

4 0
2 years ago
Read 2 more answers
______% of 200 miles is 150 miles.
Genrish500 [490]

Answer:

75%

Step-by-step explanation:

150/200 × 100 =75

6 0
3 years ago
Read 2 more answers
Let R be the region bounded by
loris [4]

a. The area of R is given by the integral

\displaystyle \int_1^2 (x + 6) - 7\sin\left(\dfrac{\pi x}2\right) \, dx + \int_2^{22/7} (x+6) - 7(x-2)^2 \, dx \approx 9.36

b. Use the shell method. Revolving R about the x-axis generates shells with height h=x+6-7\sin\left(\frac{\pi x}2\right) when 1\le x\le 2, and h=x+6-7(x-2)^2 when 2\le x\le\frac{22}7. With radius r=x, each shell of thickness \Delta x contributes a volume of 2\pi r h \Delta x, so that as the number of shells gets larger and their thickness gets smaller, the total sum of their volumes converges to the definite integral

\displaystyle 2\pi \int_1^2 x \left((x + 6) - 7\sin\left(\dfrac{\pi x}2\right)\right) \, dx + 2\pi \int_2^{22/7} x\left((x+6) - 7(x-2)^2\right) \, dx \approx 129.56

c. Use the washer method. Revolving R about the y-axis generates washers with outer radius r_{\rm out} = x+6, and inner radius r_{\rm in}=7\sin\left(\frac{\pi x}2\right) if 1\le x\le2 or r_{\rm in} = 7(x-2)^2 if 2\le x\le\frac{22}7. With thickness \Delta x, each washer has volume \pi (r_{\rm out}^2 - r_{\rm in}^2) \Delta x. As more and thinner washers get involved, the total volume converges to

\displaystyle \pi \int_1^2 (x+6)^2 - \left(7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \pi \int_2^{22/7} (x+6)^2 - \left(7(x-2)^2\right)^2 \, dx \approx 304.16<em />

d. The side length of each square cross section is s=x+6 - 7\sin\left(\frac{\pi x}2\right) when 1\le x\le2, and s=x+6-7(x-2)^2 when 2\le x\le\frac{22}7. With thickness \Delta x, each cross section contributes a volume of s^2 \Delta x. More and thinner sections lead to a total volume of

\displaystyle \int_1^2 \left(x+6-7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \int_2^{22/7} \left(x+6-7(x-2)^2\right) ^2\, dx \approx 56.70

7 0
2 years ago
Is 15.050 larger than 15.500
jeyben [28]
No its smaller because 15.05 can be converted to fraction form as 15 and 5 over 100 15.5 is converted as 15 and 50 over 100 or one half
3 0
3 years ago
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