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3 years ago

Naitik exercised for

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

<h3>Answer: Aryan spent more time exercising.</h3>

=======================================================

Explanation:

Use your calculator to convert each fraction into decimal form

2/3 = 0.67 approximately

3/4 = 0.75 exact

The decimal 0.75 is larger than 0.67, in which we can think of it like saying "75 is larger than 67".

So 0.67 < 0.75 which leads to 2/3 < 3/4.

Aryan spent more time exercising.

--------------

We could stop there, but if you wanted to know how much longer he spent exercising, then we subtract the two fractions to get

3/4 - 2/3

9/12 - 8/12

(9-8)/12

1/12

Aryan spent 1/12 of an hour longer exercising compared to Naitik

1/12 hour = (1/12)*60 = 60/12 = 5 minutes

He spent 5 extra minutes exercising.

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Notes:

2/3 hours = (2/3)*60 = 40 minutes
3/4 hours = (3/4)*60 = 45 minutes
45-40 = 5 extra minutes of exercise

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App 19.study

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Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

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