Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
D, it’s a function because the Y and X values have its own numbers , and vertical are functions . Horizontal is not a function
N + d = 20....n = 20 - d
0.05n + 0.10d = 1.35
0.05(20 - d) + 0.10n = 1.35
1 - 0.05d + 0.10d = 1.35
-0.05d + 0.10d = 1.35 - 1
0.05d = 0.35
d = 0.35/0.05
d = 7 <==== 7 dimes
n + d = 20
n + 7 = 20
n = 20 - 7
n = 13 <=== 13 nickels
Y = mx+b (slope intercept form). I imagine the point is (2,2) and m = 0. So the answer is y = 2. A sketch would be a horizontal line on the x-y plane going through (2,2).
Shee needs 448 ounces of lemonade.
448 ÷ 80 =5.8
⇒ There are 5.6 80-ounce of lemonade.
80 ounces of lemonade needed 8 lemons.
448 ounces of lemonade needed 8 x 5.6 = 44.8 lemons.
Tanisha has 38 lemons.
She does not have enough lemons.
She needs 44.8 - 38 = 7 more lemons.
Answer: <span>Tanisha needs more lemons. She needs 7 more.</span>
