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Ahat [919]
3 years ago
14

An animal shelter spends $1.50 per day to care for each cat and $3.50 per day to care for each dog. Gianna noticed that the shel

ter spent $20.50 caring for cats and dogs on Tuesday. Gianna found a record showing that there were a total of 7 cats and dogs on Tuesday. How many cats were at the shelter on Tuesday?
Mathematics
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

2 cats were cared for

Step-by-step explanation:

c= cats

d=dogs

c+d =7

1.5c+3.5d=20.50

c+d =7

solve for d

d = 7-c

substitute into 1.5c+3.5d=20.50

1.5 c + 3.5 (7-c) = 20.50

distribute

1.5c +24.5 -3.5 c = 20.5

combine like terms

24.5 -2c =20.5

subtract 24.5 from each side

-2c = -4

divide by -2

c =2


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dsp73

9514 1404 393

Answer:

  (x1, x2) = (3, -4)

Step-by-step explanation:

As with any 2-step linear equation, subtract the constant, then multiply by the inverse of the coefficient of the variable.

  \left[\begin{array}{cc}3&2\\5&5\end{array}\right]\left[\begin{array}{c}x\\y\end{array}\right]+\left[\begin{array}{c}1\\2\end{array}\right]=\left[\begin{array}{c}2\\-3\end{array}\right]\\\\\left[\begin{array}{cc}3&2\\5&5\end{array}\right]\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}1\\-5\end{array}\right]\\\\\left[\begin{array}{c}x\\y\end{array}\right]=\dfrac{1}{5}\left[\begin{array}{cc}5&-2\\-5&3\end{array}\right]\left[\begin{array}{c}1\\-5\end{array}\right]

Performing the multiplication of the matrix by the vector gives the solution.

  x = ((5)(1) +(-2)(-5))/5 = 15/5 = 3

  y = ((-5)(1) +(3)(-5))/5 = -20/5 = -4

Using your variables, x1, x2, the solution is ...

  (x1, x2) = (3, -4)

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valentinak56 [21]
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5 0
3 years ago
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Step-by-step explanation:

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