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Damm [24]
3 years ago
10

Given these two data sets, IQ-GPA and IQ-SAT, how would you predict Justin’s SAT score based on his GPA? Explain.

Mathematics
2 answers:
stira [4]3 years ago
5 0

Answer:

Use the equation of the IQ-GPA trend line to find the IQ corresponding to the given GPA.

Use the equation of the IQ-SAT trend line to find the SAT corresponding to that IQ.



BlackZzzverrR [31]3 years ago
4 0
<span>First, use the equation of the trend line to find the IQ that is expected by the GPA. Next, use the other equation of the trend line to find the SAT that is predicted by the IQ.</span>
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Factor the polynomial: 2x(x - 4) + 7 (x - 4)
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Answer:

Step-by-step explanation:

With this question, we just have to group the terms, so in this case, we can remove the common term (x - 4), and then group the rest of them

If we do that we get:

(x - 4) (2x + 7)

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8+[5×6]= i need answer asap pls
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38

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3 years ago
An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th
Irina-Kira [14]
Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

Total area to be covered by grass is the base and the four side faces and is given by \frac{20}{h}+\sqrt{320h}

Cost of the entire metal frame = 7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h

Cost of the entire grass = 8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h

Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
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