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ryzh [129]
3 years ago
6

Condense the following logs into a single log:

" id="TexFormula1" title="5log_{b} x - 6log_{b} y" alt="5log_{b} x - 6log_{b} y" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Ostrovityanka [42]3 years ago
6 0

Answer:

5\log_b(x)-6\log_b(y)=\log_b(\frac{x^5}{y^6})

Step-by-step explanation:

The given logarithmic expression is  5\log_b(x)-6\log_b(y)

We apply the rule: n\log_b(M)=\log_b(M^n)

This implies that;

5\log_b(x)-6\log_b(y)=\log_b(x^5)-\log_b(y^6)

We now apply the rule; \log_a(M)-\log_a(N)=\log_a(\frac{M}{N} )

5\log_b(x)-6\log_b(y)=\log_b(\frac{x^5}{y^6})

navik [9.2K]3 years ago
3 0

Answer:

logb(X^5 / Y^6)

Step-by-step explanation:

Given in the question an expression

5logbX - 6logbY

To Condense the following logs into a single log we will use logarithm rules

<h3>1) log power rule </h3>

5logbX = logbX^5

6logbY = logbY^6

<h3>2)log qoutient rule </h3>

ln(x/y) = ln(x)−ln(y)

logbX^5 - logbY^6 = logb(X^5 / Y^6)

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