Answer:
B but am not sure tho it's probably A
Assuming ℎ1 = 11 feet and ℎ 2 = 3 feet, the storage of the facility is going to be 603 cubic feet, which is more than 576 cubic feet
The diameter of the building has been given as 8cm
radius = d/2 = 8/2 = 4
Maximum height = h1 + h2 = 14
Find the volume of the fertilizer that is containeed in both of the trucks
2(12x4x6) = 576 feet
From the height of 14 feets we have to assume
h1 = 11 ft,
h2 = 3 ft
<h3>How to solve for volume</h3>

= 0.333*3.14*4²*3 + 3.14*4²*11
= 602.8 ft ≈ 603
Read more on volume here: brainly.com/question/12410983
<h3>I'll teach you how to solve (2w - 3)*(4w - 7)</h3>
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Apply FOIL method:
2w*4w+2w(-7)+(-3)*4w+(-3)(-7)
Apply minus/plus rules:
2*4ww-2*7w-3*4w+3*7
Simplify:
8w^2-26w+21
Your Answer Is 8w^2-26w+21
plz mark me as brainliest :)
Answer:
B.
D.
E.
Step-by-step explanation: