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Olegator [25]
3 years ago
8

The perimeter of a rectangle is 4040 yards. what are the dimensions of the rectangle with maximum area?

Mathematics
1 answer:
Ivanshal [37]3 years ago
8 0
Let x be the length and y be the width2x + 2y = 40x + y = 20change that into y = mx + b formy= 20 – x
Area =xy = x (20-x) = 20x - x^2Area=-x^2+20xcomplete the square:Area=-(x^2 – 20x + 100) +100=-(x - 10)^2 + 100This is an calculation of a parabola that opens downward with vertex at (10,100), which means maximum area of 100 happens when x, the length=10)Dimensions of the rectangle with maximum area? 10 yds. by 10 yds., a square.
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see i don't mind giving my points away..Can anyone help me solve this though for a brainlest and extra points?​
victus00 [196]

Answer:

a=17\sqrt{2}

Step-by-step explanation:

As we have 2 of the angles, we can find the third. The measure of the third angle is 45 degrees.

As this is the same measure as the other, that means that the side length will be the same.

Now was have two side lengths of 17 in a right triangle, so we can use the Pythagorean theorem to find a.

Recall that the pythagorean theorem states: a^2+b^2=c^2

In this case, a is 17, b is 17, and c is a

Knowing this, we can input our value into this formula and solve for a.

17^2+17^2=a^2\\\\289+289=a^2\\\\a=\sqrt{578} \\\\a=17\sqrt{2}

6 0
3 years ago
Read 2 more answers
HELPPP ME PLEASE I REALLY NEED HELP
aliya0001 [1]
<h3>Answer:   choice F) 12 & 1/2 square yards.</h3>

=====================================================

We'll use this formula

a & b/c = (a*c + b)/c

to convert from a mixed number to an improper fraction.

Let's convert the first mixed number to an improper fraction

a & b/c = (a*c + b)/c

3 & 3/4 = (3*4 + 3)/4

3 & 3/4 = 15/4

Repeat the same idea for the second mixed number as well

a & b/c = (a*c + b)/c

3 & 1/3 = (3*3 + 1)/3

3 & 1/3 = 10/3

--------------------

In short we have

  • 3 & 3/4 = 15/4
  • 3 & 1/3 = 10/3

Doing these conversions is useful to be able to multiply the values like so:

(15/4)*(10/3) = (15*10)/(4*3) = 150/12 = (6*25)/(6*2) = 25/2

Now use your calculator to find that 25/2 = 12.5

We can then say....

12.5 = 12 + 0.5 = 12 + (1/2) = 12 & 1/2

The answer is choice F) 12 & 1/2 square yards.

6 0
2 years ago
The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
ANTONII [103]

Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

8 0
3 years ago
Between each whole number does √199
Gala2k [10]

between 14 and 15

because

14^2 = 196

15^2 = 225


7 0
3 years ago
a group of students decided to collect as many paise (1/100 RS.) from each member of the group as is the number of members. If t
Softa [21]

Answer:

Let the no. Of members be x

Rs. 59.29 = 5929 paise

5929/x = x

x^2 = 5929

Therefore x = 77

No. Of members = 77

Hope this helps!

8 0
3 years ago
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