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4 years ago

What’s the ordered pairs of y = 10x + 18? The image is down below.

Mathematics

2 answers:

dimulka [17.4K]4 years ago

4 0

First, if ordered pairs are in the form of (x,y) then the first one means plug in x with 0. If you do that, you get y= -10(0)+18. Simplify to get y=18. So, for the first one, it is (0,18). For the next one, you plug in 1 for x. So, y=-10(1)+18. Simplify to get y=-10+18. Simplify again to get y=8. So the second one is (1,8). For the last one you have only the y value, so plug in 78 for y. So, 78=-10x+18. We want to isolate x, so subtract 18 from both sides. You get 60=-10x. Now divide by -10 to get -6=x. So, the last ordered pair is (-6,78)

kompoz [17]4 years ago

3 0

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Step-by-step explanation:

First, notice that:

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Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

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We substitute in what we had:

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Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

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