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Komok [63]
3 years ago
7

Factor completly: x^2-2x-24

Mathematics
2 answers:
lions [1.4K]3 years ago
8 0

Answer:

(x+4)(x−6)

Step-by-step explanation:

Factoring x2−2x−24

x2−2x−24

The middle number is -2 and the last number is -24.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -2

Multiply together to get -24

Can you think of the two numbers?

Try 4 and -6:

4+-6 = -2

4*-6 = -24

Fill in the blanks in

(x+_)(x+_)

with 4 and -6 to get...

(x+4)(x-6)

melisa1 [442]3 years ago
4 0
<span>x^2-2x-24 = (x - 6)(x + 4)

cause
</span>(x - 6)(x + 4)
= x^2 - 6x + 4x - 24
= x^2 - 2x - 24

answer
(x - 6)(x + 4)

hope it helps
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"If you like rock-n-roll, then you like loud music." What is the converse of this statement?
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"If  you like loud music, then you like rock-n-roll"

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we know that

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2 years ago
How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


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if 2 are real, then the others must be complex

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7 0
3 years ago
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