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konstantin123 [22]
4 years ago
15

Solve

Mathematics
1 answer:
Bas_tet [7]4 years ago
5 0
f(x)=15\cdot0.2^x\\
0.2^x=\dfrac{f(x)}{15}\\
x=\log_{0.2}\dfrac{f(x)}{15}\\\\\\
f(x)=40+1^x\\
1^x=f(x)-40\\
x=\log_1(f(x)-40)
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