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3 years ago

Describe the relationship between the area of a circle and its circumference.

Mathematics

2 answers:

MAVERICK [17]3 years ago

7 0

Answer 1. area 2. 1\2 3. radius

Step-by-step explanation:

it is trsut me i got it right on the exam

AfilCa [17]3 years ago

6 0

Answer:

Area

1/2

Radius

Step-by-step explanation:

We know that for any circle with radius r the formula for the area and circumference of the circle is given as:

Area of circle=πr².

and circumference of circle = 2πr.

Hence, to describe the relationship between the area of a circle and its circumference.

The Area of circle is 1/2 times the radius times the circumference.

( Since,

Area=1/2 × r× 2πr

Area=πr² )

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Morgarella [4.7K]

Answer:

$f'(x)=-\frac{2}{x^\frac{3}{2}}$

Step-by-step explanation:

So we have the function:

$f(x)=\frac{4}{\sqrt x}$

And we want to find the derivative using the limit process.

The definition of a derivative as a limit is:

$\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Therefore, our derivative would be:

$\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}$

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

$=\lim_{h \to 0}\frac{4(\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x})}{h}$

Place the 4 in front:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}$

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})$

Distribute:

$=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}$

Simplify: For the first term on the left, the √(x+h) cancels. For the term on the right, the (√(x)) cancel. Thus:

$=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }$

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

$= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}$

The numerator will use the difference of two squares. Thus:

$=4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Simplify the numerator:

$=4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Both the numerator and denominator have a h. Cancel them:

$=4 \lim_{h \to 0} \frac{-1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Now, substitute 0 for h. So:

$=4 ( \frac{-1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})})$

Simplify:

$=4( \frac{-1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})})$

(√x)(√x) is just x. (√x)+(√x) is just 2(√x). Therefore:

$=4( \frac{-1}{(x)(2\sqrt{x})})$

Multiply across:

$= \frac{-4}{(2x\sqrt{x})}$

Reduce. Change √x to x^(1/2). So:

$=-\frac{2}{x(x^{\frac{1}{2}})}$

Add the exponents:

$=-\frac{2}{x^\frac{3}{2}}$

And we're done!

$f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}$

5 0

3 years ago

The product of

Basile [38]

Answer:

a= 12

b=-2

Step-by-step explanation:

12 x -2 = -24

12 - (-2) = 14

12 + (-2) = 10

3 0

3 years ago

One car travel 56 miles per hour and another travels 31 miles per hour. If they start from the same place at the same time and t

Vitek1552 [10]

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Step-by-step explanation:

Given,

Speed of first car = 56 miles per hour

Speed of second car = 31 miles per hour

Let,

x be the number of hours.

Distance covered by first car = Speed * time = 56x

Distance covered by second car = 31x

According to given statement;

Difference between distance covered by both cars = 75 miles

Distance of faster car - Distance of slower car = 75 miles

$56x-31x=75\\25x=75$

Dividing both sides by 25

$\frac{25x}{25}=\frac{75}{25}\\x=3$

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Keywords: subtraction, division

Learn more about subtraction at:

#LearnwithBrainly

4 0

3 years ago

4a + 6b= 10 2a - 4b =12 what does 12a=

mixer [17]

4a + 6b = 10
2a - 4b = 12...multiply by -2
----------------
4a + 6b = 10
-4a + 8b = - 24 (result of multiplying by -2)
------------------add
14b = - 14
b = -14/14
b = -1

2a - 4b = 12
2a - 4(-1) = 12
2a + 4 = 12
2a = 12 - 4
2a = 8
a = 8/2
a = 4

so 12a = 12(4) = 48 <==

3 0

4 years ago

4(3x + 2) (Box)x+ 8 What number belongs in the box? A. 3 B. 4 C. 7 D. 12

ASHA 777 [7]

Answer:

option D 12 is correct..

in second question the student didn't multiply -3 with 4. that's the mistake he did.

hope it helps

4 0

3 years ago

Read 2 more answers