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Andrej [43]
3 years ago
12

The four digit 489A is divisible by 11. What digit does A represent?

Mathematics
1 answer:
wariber [46]3 years ago
6 0
It is 5! Hope I can help! :)
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Determine the type and number of solutions of x^2 + 10x − 25 = 0. A two real solutions B one real solution C two imaginary solut
klemol [59]

Answer:

two real solution

Step-by-step explanation:

x^2 + 10x − 25 = 0

we can solve this by finding out the value of x

lets assume the equation is   a\times x^{2}+b\times x+c=0

x=-b\pm \sqrt{(b^{2}-4ac)}\div 2a

x=-10\pm\sqrt{100+4*25}\div2

x=-5\pm5\sqrt2

then we get both real value of x

so two real solution

4 0
4 years ago
Which statements are true about triangle ABC and its translated image, A'B'C'? Select two options.
valina [46]

Answer:

t

Step-by-step explanation:

t

3 0
3 years ago
If the roots of x²-7x+k=0 are m and m-1, find the value of the constant k​
creativ13 [48]

Answer: k=12

Step-by-step explanation:

x2 - 7x + k = 0

using quadratic formula method,

x = [-b ± √(b2 - 4ac)]/2a

a = 1

b = -7

c = k

x = [-(-7) ± √((-7)2 - 4(1)(k))]/2(1)

x = [7 ± √(49 - 4k)]/2

x = [7 + √(49 - 4k)] / 2 and [7 - √(49 - 4k)] / 2

since the roots are m and m-1,

m = [7 + √(49 - 4k)] / 2 ------------ eqn(1), and

m - 1 = [7 - √(49 - 4k)] / 2 ----------- eqn(2)

add 1 to both sides of eqn(2)

m = [7 - √(49 - 4k)]/2 + 1 --------------- eqn(3)

eqn(1) = eqn(3)

[7 + √(49 - 4k)]/2 = [7 - √(49 - 4k)]/2 + 1

7/2 + (√(49 - 4k))/2 = 7/2 - (√(49 - 4k))/2 + 1

collect like terms,

(√(49 - 4k))/2 + (√(49 - 4k))/2 = 7/2 - 7/2 + 1

(√(49 - 4k))/2 + (√(49 - 4k))/2 = 0 + 1

(√(49 - 4k))/2 + (√(49 - 4k))/2 = 1

multiply through by 2

√(49 - 4k) + √(49 - 4k) = 2

2√(49 - 4k) = 2

divide both side by 2

√(49 - 4k) = 1

square both sides

49 - 4k = 1

collect like terms,

4k = 49 - 1

4k = 48

divide both sides by 4

k = 48/4

k = 12

6 0
3 years ago
A staff member at UF's Wellness Center is interested in seeing if a new stress reduction program will lower employees systolic b
Yuri [45]

Answer:

A. On average the blood pressure levels before the stress reduction program were significantly higher than the systolic blood pressure levels after the stress reduction program, at 95% confidence level

Step-by-step explanation:

The confidence interval parameters is intended to detect if the new stress reduction program will lower the systolic blood pressure levels of employees

The difference between the the mean systolic blood pressure levels taken = The before systolic pressure - The after systolic blood pressure

The 95% confidence interval obtained = (5.6, 10.2)

Therefore, given that the values of the difference between the means are both positive, then there a difference as the confidence interval does not include zero (0), and at the 95% confidence level, the average systolic blood pressure levels before the stress reduction program are higher than the average systolic blood pressure levels after the program

5 0
3 years ago
One more than the product of 17 and Matt's savings
velikii [3]

Answer:

17m=2

Step-by-step explanation:

hey plz pick mine as the brainliest?

8 0
3 years ago
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