Question

Factor. 100x^2 − 20xy + y^2

Answer 1

100x²− 20xy + y²=

(10x-y) (10x-y) or (10x-y)²

Answer 2

Answer:

the factor of $100x^2-20xy+y^2$  are, $10x-y$ and $10x-y$

Step-by-step explanation:

Using the identity rule:

$(a-b)^2 = a^2-2ab+b^2$

Factor the given equation:

$100x^2-20xy+y^2$

We can write this as:

$10^2x^2-20xy+y^2$

Use: $(ab)^2 = a^2 \cdot b^2$

⇒$(10x)^2-2(10x)y+y^2$

Apply the  identity rule:

$(10x-y)^2$

Therefore, the factor of $100x^2-20xy+y^2$  are, $10x-y$ and $10x-y$