The probability that a randomly selected adult has an IQ less than
135 is 0.97725
Step-by-step explanation:
Assume that adults have IQ scores that are normally distributed with a mean of mu equals μ = 105 and a standard deviation sigma equals σ = 15
We need to find the probability that a randomly selected adult has an IQ less than 135
For the probability that X < b;
- Convert b into a z-score using z = (X - μ)/σ, where μ is the mean and σ is the standard deviation
- Use the normal distribution table of z to find the area to the left of the z-value ⇒ P(X < b)
∵ z = (X - μ)/σ
∵ μ = 105 , σ = 15 and X = 135
∴ 
- Use z-table to find the area corresponding to z-score of 2
∵ The area to the left of z-score of 2 = 0.97725
∴ P(X < 136) = 0.97725
The probability that a randomly selected adult has an IQ less than
135 is 0.97725
Learn more:
You can learn more about probability in brainly.com/question/4625002
#LearnwithBrainly
Answer:
m < 36
yes, Jamie is correct.
Step-by-step explanation:
I've bolded the statements that you can put down to show your work
the maximum that Jamie is willing to practice for the week is 300 minutes, so you can start by creating an inequality for that.
total minutes throughout the week < 300
next, you know that a week is monday through friday + the weekend, and the amount of minutes Jamie will practice for the weekend is already given.
so, you can rewrite the earlier inequality like so
Monday through Friday practice + 120 < 300
since Jamie plans to practice the same amount of time (m) for each day, and there are 5 days between monday and friday, you can substitute values in the equation
5m + 120 < 300
simplify
5m < 300 - 120
5m < 180
m < 36
since half an hour is 30 minutes, the answer is yes, Jamie's claim is correct.
The best estimate would be 181.4
Step-by-step explanation:
Check to see if there is a number before (to the left of) the decimal. If there is, this number is the whole number of the fraction. So, 3 is the whole number. Place the number that falls after (to the right of) the decimal in the numerator; then use the decimal placement to determine the denominator.
<span>The set of whole numbers includes zero, all negative integers, and all positive integers. Be sure to exclude any decimals, fractions etc. Good luck~ c:</span>