Answer:
One way to factor equation is to find the zeros. Its obvious that x=-1 is solution for this. So one factor is (x+1)
the next factor should include 2x at first (because we have 2x^2 in the equation which can not be made any other way)
Let's suppose the factor is (x+1)(2x+b)
Since we do not know what is b open the brackets 2x^2+bx+2x+b. If this is equal to 2x^2+5x+3 then b=3. We are left with (x+1)(2x+3)=2(x+1)(x+3/2)
Would go for other shorter solutions, but they require some deeper understanding like Horner's scheme,Fermat's Theorem or even deeper which I assume You will not understand)
I think the answer might be C i hope this helps you
Answer:
Step-by-step explanation:
haha dude ur in my class
Hope this helped the answer is in purple
7 x² + 7 y² - 28 x + 42 y - 35 = 0 /: 7
x² + y² - 4 x + 6 y - 5 = 0
( x² - 4 x + 4 ) + ( y² + 6 y + 9 ) - 4 - 9 - 5 = 0
The equation in the standard form is:
( x - 2 )² + ( y + 3 )² = 18
The center is at the point ( 2, - 3 ).
Its radius is: √18 = 3√2 units.