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Nuetrik [128]
3 years ago
14

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. A(n) = –3 + (n – 1)(–2.2)

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
A(n) = a1 + (n - 1) * d
A(n) = -3 + (n - 1) * -2.2
n = term to find
a1 = first term = -3
d = common difference = -2.2

we can already see that the first term is -3 <==

4th term..
A(4) = -3 + (4 - 1) * -2.2
A(4) = -3 + 3(-2.2)
A(4) = -3 - 6.6
A(4) = - 9.6 <== 4th term

10th term...
A(10) = -3 + (10 - 1) * -2.2
A(10) = -3 + 9 * - 2.2
A(10) = -3 - 19.8
A(10) = - 22.8 <===10th term

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2 years ago
The sum of two integers is 61 and their difference is 1. Find the integers.
musickatia [10]

We can find this integer using a system of equations.  The first thing we look at is the first sentence.

Let's call X The first integer,

Let's call Y the second integer.


So, X+Y=61 and X-Y= 1


Using Substituion on the second equation, we get

X=Y+1

(Now we plug in Y+1 into the second equation for X)

So,

(Y+1)+Y=61

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7 0
3 years ago
F(5)=3|x+11|-4, find f(5)
deff fn [24]

Answer:

f(5) = 44

Step-by-step explanation:

f(x) = 3|x+11| -4

let x =5

f(5) = 3|5+11| -4

     = 3|16| -4

      = 3*16 -4

    = 48 -4

   = 44

5 0
3 years ago
Read 2 more answers
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