Given that the slope of a line is 1/3, what is the slope of a line that is pependicular to it ?
1 answer:
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ANSWER
EXPLANATION
The given function is,
This function has a period of
just as the parent function
A sample period of this parent function is
![[ 0 , 2\pi]](https://tex.z-dn.net/?f=%5B%200%20%2C%202%5Cpi%5D)
Which begins at zero.
For the transformed function,
There has been a horizontal shift of
to the left.
The transformed function will have a sample period,
![[ - \frac{\pi}{4} , \frac{7\pi}{4} ]](https://tex.z-dn.net/?f=%5B%20-%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2C%20%5Cfrac%7B7%5Cpi%7D%7B4%7D%20%5D)
Therefore a sample period begins at
EXPLANATION
The given function is,
This function has a period of
just as the parent function
A sample period of this parent function is
Which begins at zero.
For the transformed function,
There has been a horizontal shift of
to the left.
The transformed function will have a sample period,
Therefore a sample period begins at
Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>Suppose an infinity sequence defined by:
Then we have to calculate the following limit:
If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:
Hence the limit is:
Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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