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3 years ago

What is the coefficient of the xy term in the expression below? 2x + 3y - 4xy - 10

Mathematics

2 answers:

max2010maxim [7]3 years ago

7 0

Answer:

The coefficient of the xy term in the expression is -4

Step-by-step explanation:

In an algebric expression, the coefficient is the number attached to a variable x,y,z.

For example in algebric equation 4x + 3y = 12

The coefficient of x is 4 and the coefficient of y is 3.

So in the given term 2x + 3y - 4xy - 10,

The coefficient of the xy term is -4

alukav5142 [94]3 years ago

3 0

For this case we have the following expression:

$2x + 3y-4xy-10$

By definition, a coefficient is the term that accompanies one or more variables.

For example:

$3x + 5$

The coefficient of the linear term is 3.

So, in the given expression we have to:

-4 is the term that accompanies the variables xy.

Answer:

-4

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Help on college algebra, question is on the picture!

kodGreya [7K]

$\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$ is given
here , $\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$
or, $\frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x}$
or, $\frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x}$
or,7x²+3x-4=-4
or,7x²+3x=0
or,x(7x+3)=0
Either,x=0| Or,7x+3=0
|or,7x=-3
|or,x= $\frac{-3}{7}$
So , the solution set is S={0,- $\frac{3}{7}$ }

8 0

3 years ago

5. David Read's the problem:

vladimir1956 [14]

Answer:

No, David's answer does not seem reasonable.

Let x= original purchase amount

25x = $10.25, so solve for x by dividing both sides by .25, and you get x = $41.

If the shirt was $18, the shorts must have been $41-$18 = $23 NOT $41.

Step-by-step explanation:

7 0

3 years ago

Use the sample information 11formula13.mml = 37, σ = 5, n = 15 to calculate the following confidence intervals for μ assuming th

bija089 [108]

Answer & Step-by-step explanation:

The confidence interval formula is:

I (1-alpha) (μ)= mean+- [(Z(alpha/2))* σ/sqrt(n)]

alpha= is the proposition of the distribution tails that are outside the confidence interval. In this case, 10% because 100-90%

σ= standard deviation. In this case 5

mean= 37

n= number of observations. In this case, 15

(a)

Z(alpha/2)= is the critical value of the standardized normal distribution. The critical valu for z(5%) is 1.645

Then, the confidence interval (90%):

I 90%(μ)= 37+- [1.645*(5/sqrt(15))]

I 90%(μ)= 37+- [2.1236]

I 90%(μ)= [37-2.1236;37+2.1236]

I 90%(μ)= [34.8764;39.1236]

(b)

Z(alpha/2)= Z(2.5%)= 1.96

Then, the confidence interval (90%):

I 95%(μ)= 37+- [1.96*(5/sqrt(15)) ]

I 95%(μ)= 37+- [2.5303]

I 95%(μ)= [37-2.5303;37+2.5303]

I 95%(μ)= [34.4697;39.5203]

(c)

Z(alpha/2)= Z(0.5%)= 2.5758

Then, the confidence interval (90%):

I 99%(μ)= 37+- [2.5758*(5/sqrt(15))

I 99%(μ)= 37+- [3.3253]

I 99%(μ)= [37-3.3253;37+3.3253]

I 99%(μ)= [33.6747;39.3253]

(d)

C. The interval gets wider as the confidence level increases.

8 0

3 years ago

A car dealership sold 480 vehicles last year. Of these vehicles, 15% were minivans.

natulia [17]

You can use my photo as reference but its going to be 15/100 of 480

7 0

2 years ago

The length of a living room is 12 feet and its width is 1012 feet. The length of the room is being expanded by x feet. Choose an

Ivanshal [37]

Answer:

Option C. 10.5(12 + x) square feet

Option E. (126 + 10.5x) square feet

Step-by-step explanation:

step 1

Find the area of the original living room

we know that

The area of the original living room is equal to

$A=LW$

we have

$L=12\ ft\\W=10\frac{1}{2}\ ft=10.5\ ft$

substitute

$A=(12)(10.5)=126\ ft^2$

step 2

Find the new area of the living room

The length of the room is being expanded by x feet

we have

$L=(12+x)\ ft\\W=10.5\ ft$

The new area is

$A=10.5(12+x)\ ft^2$

The expanded form of the expression is

Apply distributive property

$A=10.5(12)+10.5(x)\\A=(126+10.5x)\ ft^2$

6 0

3 years ago