Identify the y-intercept
1.)v^2 - 11v+30=0
2.) v^2 + 2v - 8=0
1 answer:
We know that y-intercepts are the values found when x=0; 1) v²-11v+30=y <-- replace 0 as y and substitute x=0 (0)²-11(0)+30=y 30=y The y-intercept is 30 here. 2) v²+2v-8=y <-- repeat the above steps (0)²+2(0)-8=y -8=y The y-intercept is -8 here As you can notice, the c value in the standard equation (ax²+bx+c=y) is the y-intercept. Hope I helped :)
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