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4 years ago

D Question 12 (-3, 3) and (2, -7) What is the slope of the line?

Mathematics

1 answer:

solmaris [256]4 years ago

6 0

Answer:

m=-2

Step-by-step explanation:

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6.5 + m = 17 <br><br> solve for m

Hunter-Best [27]

Answer:

m=10.5

Step-by-step explanation:

For this equation you could do the long or simple way, I will be using the easier way, you can take the 17 and 6.5, subtract the 17 by the 6.5 and you get 10.5.

m=10.5

I hope that this has helped you, have an great day.

3 0

3 years ago

Read 2 more answers

Ay 4 function is represented by the equation y = 2(x + 1). Complete the table and graph for the function. Does the quation repre

aleksklad [387]

Use point (-3,2):

2 = 4*(-3) + b

b = 2 +12

b = 14

The equation is y = 4x + 14

Step-by-step explanation:

3 0

2 years ago

WILL MARK BRAINLIST please help :)

zloy xaker [14]

Answer:

y=-3/4x+2

y=2/5x-3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3. (2 points) Select one: a. x = -4

Kay [80]

Answer:

Step-by-step explanation:

$\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}$

Domain:

$x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3$

solution:

$\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}$

use <em>(a - b)(a + b) = a² - b²</em>

$\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}$

multiply both sides by (x - 3) ≠ 0

$\dfrac{4(x-3)}{x}+\dfrac{4(x-3)}{(x-3)(x+3)}=\dfrac{3(x-3)}{x-3}$

cancel (x - 3)

$\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3$

subtract $\frac{4(x-3)}{x}$ from both sides

$\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}$