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Andrews [41]
3 years ago
8

Find the arc length of a central angle of pi/4 in a circle whose radius is 8 inches

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
The formula of the arc is:

Arc Length = 2πR.(C°/360°), where R is the radius, C°(in degrees) is the central angle of the arc:

We are given:
R = 8 in
Central angle = π/4 ≈ (180°/4) = 45°
Length of the arc= 2π x 8 x (45°/360°) →16π(1/8) :

Length of the arc = 2π in (answer B)
Solnce55 [7]3 years ago
3 0
arc \ length =\theta*r \ \ \ [\theta= \frac{ \pi }{4}; \ \ r=8] } \\  \\  arc \ length = \frac{ \pi }{4} *8 =2 \pi  \ \ in
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Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.
SSSSS [86.1K]

Answer:

  \dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

  -x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}

6 0
3 years ago
7x(-3) x (-2)^2<br> help please!
Anvisha [2.4K]
    [7×(-3)]   ×   (-2)²
=     (-21)    ×    4
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5 0
3 years ago
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Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
3 years ago
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Kryger [21]

Answer:

Division Expression - 7 ÷ 3

Unit Form - 21 thirds ÷ 3 = 7

Improper Fraction 7/3

Step-by-step explanation:

Hope this helps!! <3

7 0
3 years ago
285y = 15 what’s the solution
lions [1.4K]

Answer:

285y = 15\\y = \frac{15}{285}\\y = \frac{1}{19}

Step-by-step explanation:

You have to divide the entire equation by 285 to get y alone.

Then, simplify the fraction to get 1/19.

7 0
3 years ago
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