F(x) = X^2 - 11x - 60
Two terms that multiply to -60 and add to -11 so...
F(x) = (X - 15) (x + 4)
Your x-intercepts would be 15 and -4.
To factor this fraction, you have be be aware of two special factoring formula:
a^3<span> + </span>b^3<span> = (</span>a<span> + </span>b)(a^2<span> – </span>ab<span> + </span>b^2<span>)
</span><span>(a+b)³ = a³ + 3a²b + 3ab² + b³
You can see the top part in this case is (x+y)^3, and the bottom (denominator) can be factor into (x+y)(x^2-xy+y^2)
we can cancel (x+y), so what we have left is (x+y)^2/(x^2-xy+y^2)
or (x^2+2xy+y^2)/(x^2-xy+y^2)
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Answer:
An integer is always a whole number
Step-by-step explanation:
