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yan [13]
3 years ago
9

The trapezoid has an area of 1,575 cm2, Which equation could you solve to find the height of the trapezoid?

Mathematics
2 answers:
saul85 [17]2 years ago
5 0

Hello!

The trapezoid has an area of 1,575 cm2, Which equation could you solve to find the height of the trapezoid?

Data:

B (Larger base) = 63 cm

b (Minor base) = 27 cm

h (height) = ?

A (area) = 1,575 cm²  

Formula:

A = \dfrac{(B+b)*h}{2}

Substitute:

1,575 = \dfrac{(63+27)*h}{2}

1,575 = \dfrac{\diagup\!\!\!\!\!90^{45}*h}{\diagup\!\!\!\!2^1}\:\:\to\:\:\:1,575 = 45*h\:\:\to\:\:\boxed{\boxed{45h = 1,575}}\end{array}}\qquad\checkmark

Answer:

\textcircled{D}\:45h = 1,575

________________________

I Hope this helps, greetings ... Dexteright02! =)

Contact [7]3 years ago
4 0
The Area of the trapezoid has the formula of:
Area = (a + b) / 2 * h

In order for us to get the equation for the height, substitute the values that are present.
1,575 = (63 + 27) / 2 * h
1575 = 45h

So the correct answer is letter D. 45h = 1575
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The length of the box is 2x - 2 and the width is x - 5. Find the perimeter. (HINT: p= 2L + 2W) Choose one.
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Answer:

Option D: 6x-14 is the correct answer.

Step-by-step explanation:

Given that:

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Width of the box = W = x-5

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7 0
3 years ago
WILL GIVE A BRAINLEST
Gnoma [55]

Answer: "No, the triangles are not necessarily congruent." is the correct statement .


Step-by-step explanation:

In ΔCDE, m∠C = 30° and m∠E = 50°

Therefore by angle sum property of triangles

m∠C+m∠D+m∠E=180°

⇒m∠D=180°-m∠E-m∠C=180°-30°-50°=100°

⇒m∠D=100°

In ΔFGH, m∠G = 100° and m∠H = 50°

Similarly m∠F +∠G+m∠H=180°

⇒m∠F=180°-∠G-m∠H=180°-100°-50=30°

⇒m∠F=30°

Now ΔCDE and ΔFGH

m∠C=m∠F=30°,m∠D=m∠G=100°,m∠E=m∠H=50°

by AAA similarity criteria  ΔCDE ≈ ΔFGH but can't say congruent.

Congruent triangles are the pair of triangles in which corresponding sides and angles are equal . A congruent triangle is a similar triangle but a similar triangle may not be a congruent triangle.


8 0
3 years ago
Read 2 more answers
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