All categories

4 years ago

A cubed shaped paperweight has a volume of 216 cm³ What is the length of the paper weight?

1 answer:

4 0

Answer: The length of the paper weight would be 6 cm.

Explanation: Since the object is a cube that means all sides are the same length so to solve you would do 3√216 and your answer would be 6.

You might be interested in

Given the function f(x) = −5x2 − x + 20, find f(3). −28 −13 62 64

Katyanochek1 [597]

Answer:

Option (a) is correct.

The value of given function $f(x)=-5x^2-x+20$ at x = 3 is -28

Step-by-step explanation:

Given : Function $f(x)=-5x^2-x+20$

We have to find the value of given function at x = 3

Consider the given function $f(x)=-5x^2-x+20$

Since, we have tof ind the value of function at x = 3

Put x = 3 in given function f(x)

$f(3)=-5(3)^2-(3)+20$

Simplify, we have,

$f(x)=-45-3+20=-28$

Thus, the value of given function $f(x)=-5x^2-x+20$ at x = 3 is -28

5 0

3 years ago

Read 2 more answers

Help with this question please

nadya68 [22]

Answer:

2/16 or 2:16

Step-by-step explanation:

tell me if its wrong

6 0

3 years ago

Write an equation of the line that passes through (−1,3) and is parallel to the line y=2x+2

Komok [63]

Start off by writing the equation y = mx - b. Then plug in what you do know

3 = 2(-1) - b (m is the slope and parallel lines have the same slope). Then solve

3 = -2 - b

+2 +2

5 = b

So y = 2x + 5

6 0

3 years ago

What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

3 years ago

Please help me with dis ion understand pwese help me :(

Morgarella [4.7K]

Answer:

The formula for calculating the circumference of a circle is 2*pi*r. Because pi does not have an end, we'll use 3.14, since that is the approximate value of pi.

2*6*3.14 = 37.68

The outer rim of the pool is about 37.68 meters long

Step-by-step explanation:

It’s probably 40 because it says about how long not exactly.

I hope this helped

6 0

3 years ago

Read 2 more answers