For each working age people asked, there are only two possible outcomes. Either they are in the labor force, or they are not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability:

Expected value for the participation rate: The expected value is the probability of a success. In this problem, a success is a working age people being in the labor force. 63.7% of them are. So $\pi = 0.637$ . This means that the expected participation rate is 0.637.

Standard error for the participation rate:

The standard error is given by the following formula:

$\sigma = \sqrt{\frac{\pi(1-\pi)}{n}}$ .

In this problem, 120 people are asked, so $\pi = 120$

$s = \sqrt{n\pi(1-\pi)} = \sqrt{\frac{0.637*(1-0.637)}{120}} = 0.04397$ .

So the standard error is 0.04397

8 0

3 years ago

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Does anyone know how to do this? I’ve been trying to figure this out for the past hour and I can’t please help

Vsevolod [243]

They want to know the area of the letters that are besides it or they want or know what points they are at.

5 0

3 years ago

Need help with all questions !!! Get a brainiest answer and a thanks !!

stich3 [128]

1) carrots= 5/12 peas= 2/12 potatoes=1/12
corn= 4/12

2) there are more carrots than peas. there are more corn than potatoes.

3) 2/3

4) separate like number 3 but instead of corn put carrots and leave the peas.

6 0

3 years ago