Question

First, we need to find the radius: r = sqrt((-3)^2 + 1^2) = sqrt(10) sin ( theta) = y/r = 1/sqrt(10) = sqrt(10)/10 cos (theta) = x/r = -3/sqrt(10) = -3sqrt(10)/10 tan(theta) = y/x = -1/3

Answer 1

r = sqrt(10) = sqrt(10) sin(0) = y/r = 1/sqrt(10) = (cos(0))/sqrt(10) = x/r = -3/sqrt(10) = -(3 tan(0))/sqrt(10) = y/x = -1/3.