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monitta
3 years ago
7

The distance between the point (-3,4) and the point of origin

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

5

Step-by-step explanation:

1) origin point is (0;0);

2) the required distance is:

d=\sqrt{(-3-0)^2+(4-0)^2} =5.

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What is the solution <br> to 1/2n+3=6
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n in (-oo:+oo)

(1/2)*n-3 = 6 // - 6

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1/2*n-9 = 0 // + 9

1/2*n = 9 // : 1/2

n = 9/1/2

n = 18

n = 18

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B

Step-by-step explanation:

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1/3 + ( -2 1/4) Solve this equation and show your work!<br> answer has to be a number!
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<em>-1.9</em>

Step-by-step explanation:

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Vinil7 [7]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Assuming that s = 18,000 is a reasonable estimate for what sample size would be needed to ensure that we could estimate the true
djverab [1.8K]

Answer:

The minimum sample size required is 71.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

It is provided that the population standard deviation <em>σ</em> can be estimated by the sample standard deviation <em>s</em>.

The given information is:

<em>s</em> = 18000,

Margin of error = $4200.

Confidence level = 95%

The <em>z</em>-value for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Compute the sample size required as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

         =[\frac{18000\times 1.96}{4200}]^{2}

         =70.56\\\approx71

Thus, the minimum sample size required is 71.

3 0
3 years ago
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