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Juli2301 [7.4K]
3 years ago
9

I NEED HELP NOW PLEASE!!!!!

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
3 0
4 plus i square root of 11, is your answer.
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Can see please help me with the 2 equations (in the picture) find x
Lunna [17]

Answer:

1. x = 2

2. couldn't figure out. sorry

Step-by-step explanation:

8 0
3 years ago
If (-1,4) and (3,-2) are end points of diameter of the circle, then the equation of the circle is
Volgvan

Answer:

If you've more doubts you can ask :)

Step-by-step explanation:

If the centre of a circle is (a, b) and radius r, then the equation of the circle is :

(x - x)^2 + (y-b)^2 = r^2

<em><u>First we will find the centre, (a , b): </u></em>

<em><u /></em>a = \frac{3+(-1)}{2} = \frac{2}{2} = 1\\\\b = \frac{-2 + 4}{2} = \frac{2}{2} = 1<em><u /></em>

<em><u>Find radius:</u></em>

Radius, r = \frac{Diameter}{2}

Diameter is the distance between (-1, 4) and (3, -2)

diameter = \sqrt{(x_2 - x_1)^2 +(y_2-y_1)^2} \\\\

             = \sqrt{(3-(-1)^2 + (-2-4)^2} \\\\=\sqrt{16 + 36}\\\\=\sqrt{52}\\\\=\sqrt{4 \times 13}\\\\=2\sqrt{13}    \ units

Therefore , r = \frac{2 \times \sqrt{13} }{2} = \sqrt{13}  \ units

<em><u>Equation of the circle is :  </u></em>

                                 (x - 1)^2 +(y-1)^2 = 13<em><u></u></em>

4 0
3 years ago
What have I done wrong and where please help me
lys-0071 [83]
12x - 18 - 4x -2
12x - 4x = 8x (yours 12x - 4x = 8)
-18 - 2 = -20 (yours -18 -1 = 17)

answer:

8x - 20
6 0
3 years ago
A jar contains n nickels and d dimes. There are 24 coins in the jar, and the total value of the coins is $1.90. How many nickels
oee [108]

Answer:14 dimes 10 nickels

Step-by-step explanation:

24 coins total

14 X.10 = 1.40

10 x .05 = .50

1.40 + .50 = 1.90

3 0
3 years ago
A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac
sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant =  0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g

     

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0
3 years ago
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