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3 years ago

I NEED HELP NOW PLEASE!!!!!

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

3 0

4 plus i square root of 11, is your answer.

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Can see please help me with the 2 equations (in the picture) find x

Lunna [17]

Answer:

1. x = 2

2. couldn't figure out. sorry

Step-by-step explanation:

8 0

3 years ago

If (-1,4) and (3,-2) are end points of diameter of the circle, then the equation of the circle is

Volgvan

Answer:

If you've more doubts you can ask :)

Step-by-step explanation:

If the centre of a circle is (a, b) and radius r, then the equation of the circle is :

$(x - x)^2 + (y-b)^2 = r^2$

First we will find the centre, (a , b):

$a = \frac{3+(-1)}{2} = \frac{2}{2} = 1\\\\b = \frac{-2 + 4}{2} = \frac{2}{2} = 1$

Find radius:

$Radius, r = \frac{Diameter}{2}$

Diameter is the distance between (-1, 4) and (3, -2)

$diameter = \sqrt{(x_2 - x_1)^2 +(y_2-y_1)^2} \\\\$

$= \sqrt{(3-(-1)^2 + (-2-4)^2} \\\\=\sqrt{16 + 36}\\\\=\sqrt{52}\\\\=\sqrt{4 \times 13}\\\\=2\sqrt{13} \ units$

Therefore , $r = \frac{2 \times \sqrt{13} }{2} = \sqrt{13} \ units$

Equation of the circle is :

$(x - 1)^2 +(y-1)^2 = 13$

4 0

3 years ago

What have I done wrong and where please help me

lys-0071 [83]

12x - 18 - 4x -2
12x - 4x = 8x (yours 12x - 4x = 8)
-18 - 2 = -20 (yours -18 -1 = 17)

answer:

8x - 20

6 0

3 years ago

A jar contains n nickels and d dimes. There are 24 coins in the jar, and the total value of the coins is $1.90. How many nickels

oee [108]

Answer:14 dimes 10 nickels

Step-by-step explanation:

24 coins total

14 X.10 = 1.40

10 x .05 = .50

1.40 + .50 = 1.90

3 0

3 years ago

A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac

sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

$N_{t} = N_{0}e^{-\lambda t}$

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant = 0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

$N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g$

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0

3 years ago