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Natasha2012 [34]
2 years ago
5

Kindly solve this question 6 too !!

Mathematics
1 answer:
Shkiper50 [21]2 years ago
7 0

Answer:

x=1

Step-by-step explanation:

~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1

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Answers:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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4 0
2 years ago
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3 years ago
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Answer:

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