Answer:
f(x) = (4x - 1)(2x + 1)
The zeros of the function are
and
.
Step-by-step explanation:
The given quadratic expression is 8x² - 2x - 3.
Now, the factorization of this quadratic expression gives:
f(x) = 8x² - 2x - 3
⇒ f(x) = 8x² - 6x + 4x - 3
⇒ f(x) = 2x(4x - 3) + 1(4x - 3)
⇒ f(x) = (4x - 1)(2x + 1)
Hence, the zeros of the function are
and
. (Answer)
Answer:
The answer is y = 8/3x + 4/5yx - 131/5
Step-by-step explanation:
Hope that helps. :)
Can you mark me Brainliest
Answer:
Option A is correct.
Step-by-step explanation:
Given an isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. we have to find the area of isosceles trapezoid.
An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14.
From the figure attached , we can see an isosceles trapezoid ABCD,
AB = 8cm and CD=14cm
So we have to find the value of AE which is the height of Trapezoid in order to find area.
In ΔAED
![tan\angle 45 =\frac{AE}{ED}](https://tex.z-dn.net/?f=tan%5Cangle%2045%20%3D%5Cfrac%7BAE%7D%7BED%7D)
⇒ ![AE=1\times 3](https://tex.z-dn.net/?f=AE%3D1%5Ctimes%203)
∴ AE = DE =3cm
![\text{The area of the trapezoid=}\frac{h}{2}\times (a+b)](https://tex.z-dn.net/?f=%5Ctext%7BThe%20area%20of%20the%20trapezoid%3D%7D%5Cfrac%7Bh%7D%7B2%7D%5Ctimes%20%28a%2Bb%29)
h=3cm, a=14cm, b=8cm
![Area=\frac{3}{2}\times(14+8)=\frac{3}{2}\times 22=33 units^2](https://tex.z-dn.net/?f=Area%3D%5Cfrac%7B3%7D%7B2%7D%5Ctimes%2814%2B8%29%3D%5Cfrac%7B3%7D%7B2%7D%5Ctimes%2022%3D33%20units%5E2)
hence, ![\text{The area of the trapezoid is }33 units^2](https://tex.z-dn.net/?f=%5Ctext%7BThe%20area%20of%20the%20trapezoid%20is%20%7D33%20units%5E2)
Option A is correct.
Uh im guessing D, D sounds right imo