Steal; Anion
This is the answer because phosphorous is very electronegative.
Answer:
V₁ = 228 mL
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist must prepare 575 mL of 50.0 mM aqueous potassium permanganate (KMnO₄) working solution. He'll do this by pouring out some 0.126M aqueous potassium permanganate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the potassium permanganate stock solution that the chemist should pour out. Round your answer to 3 significant digits.</em>
<em />
We want to prepare 575 mL (V₂) of a 50.0 mM solution (C₂). To do so, we start, from a stock solution of concentration C₁ = 0.126 M. In order to find the volume V₁ that the chemist should pour out, we will use the dilution rule.
C₁ × V₁ = C₂ × V₂
0.126 M × V₁ = 50.0 mM × 575 mL
0.126 M × V₁ = 50.0 × 10⁻³ M × 575 mL
V₁ = 228 mL
Answer:
Phosphorus
Explanation:
Group V elements- Nitrogen, Phosphorous
period 3- Sodium, Magnesium, Aluminium, Silicon , Phosphorous, Sulphur, Chlorine and Argon
Group v and period 3 is phosphorus
Helium (He)
Explanation:
In the picture we see the following elementary particles:
2 electrons - the two spheres with negative charge which orbit around the nucleus
2 protons - the two spheres with positive charge in the nucleus
2 neutrons - the two spheres with no charge in the nucleus
The element will be Helium (He), because it have the atomic number 2 and the mass number 4, which means it contains 2 electrons, 2 protons and 2 neutrons.
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