Question

0.25 L of aqueous solution contains 0.025g of HCLO4 (strong acid) what will be the Ph of the solution g

Answer 1

Answer:

The pH of the solution will be 3

Explanation:

The strength of acids is determined by their ability to dissociate into ions in aqueous solution. A strong acid is any compound capable of completely and irreversibly releasing protons or hydrogen ions, H⁺. That is, an acid is said to be strong if it is fully dissociated into hydrogen ions and anions in solution.

Being pH=- log [H⁺] or pH= - log [H₃O⁺] and being a strong acid, all the HClO₃ dissociates:

HClO₄      +    H₂O        →      H₃O⁺      +      ClO₄-  

So: [HCLO₄]= [H₃O⁺]

The molar concentration is:

$molar concentration=\frac{number of moles of solute}{volume solution}$

The molar mass of HClO₄ being 100 g / mole, then if 100 grams of the compound are present in 1 mole, 0.025 grams in how many moles are present?

$moles of HClO_{4} =\frac{0.025 grams*1 mole}{100 grams}$

moles of HClO₄= 0.00025

Then:

$[HClO_{4}]=\frac{0.00025 moles}{0.25 L}$

$[HClO_{4}]=0.001 \frac{ moles}{ L}$

Being [HCLO₄]= [H₃O⁺]:

pH= - log 0.001

pH= 3

The pH of the solution will be 3