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Nuetrik [128]
3 years ago
11

The business college computing center wants to determine the proportion of business students who have personal computers (PC's)

at home. If the proportion exceeds 30%, then the lab will scale back a proposed enlargement of its facilities. Suppose 250 business students were randomly sampled and 75 have PC's at home. Find the rejection region for this test using a = .05
- reject h is z is greater than 1.645




reject h is z= 1.645




reject h if z is less than -1.645




reject h if z is greater than 1.96 or z is less than -1.96
Mathematics
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

Option A) reject null hypothesis if z is greater than 1.645

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 250

p = 30% = 0.3

Alpha, α = 0.05

Number of women belonging to union , x = 75

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.3\\H_A: p > 0.3

This is a one-tailed(right) test.

Rejection Region:

z_{critical} \text{ at 0.05 level of significance } = 1.645

So, the rejection region will be

z > 1.64

That is we will reject the null hypothesis if the calculated z-statistic is greater than 1.645

Option A) reject null hypothesis if z is greater than 1.645

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In a survey of 100 people, 60 like farming, 65 like civil service. Draw a venn-diagram and find the number of people who like fa
MAXImum [283]

Answer:

Ur question is wrong..

Step-by-step explanation:

In a survey of 100 people, 60 like farming and 65 like civil service?

<u>60+65=125</u>..?

7 0
1 year ago
Marcus wants to use a model to determine the difference
grigory [225]

Electron transfer theory describes the parameters which control the rate at which an electron is transferred from one atom or molecule to another.

<h3>What was the basic principle of Marcus theory?</h3>
  • In theoretical chemistry, Marcus theory is a theory originally developed by Rudolph A. Marcus, starting in 1956, to explain the rates of electron transfer reactions – the rate at which an electron can move or jump from one chemical species.
  • Marcus' method (also referred to as Marcus's method and Method of Marcus) is a structural analysis method which was designed to design concrete slabs with rectangular, orthogonal shapes. It represents an adaptation of the strip method.
  • Marcus Hush theory (M-H theory) was developed in 1956 by Rudolph A. Marcus which explains the fundamentals of the redox/ electron transfer reactions in terms of the rate of jumping/moving an electron from oxidant species (electron donor) to the reductant (electron acceptor).
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We want to see how we can model the difference: -8 - 3 + 3

The correct option is D:

"add 3 positive counters and 3 negative counters"

We know that Marcus starts with 8 negative counters, corresponding to the first term in our difference.

Now, let's study the math of our expression.

-8 - 3 + 3

Remember that we can perform the operation in any order we want, so we can write this as:

-8 + (-3 + 3)

Notice that the thing inside the parentheses is equal to zero, so we have:

- 8 + (-3 + 3) = -8

So to not change the value, we add 3 and we subtract 3.

Now if we have 8 negative counters, and we want to add 3 positive counters and not change the value, then we also need to add 3 negative counters to "cancel" the 3 positive counters we added.

Then the correct option is D.

To learn more about Marcus refer to,

brainly.com/question/23140234

#SPJ1

8 0
1 year ago
87 POINTS PLZ HELP Aman is adding –17 + 9. He wants to write –17 as the sum of two numbers so that one of the numbers, when adde
Pie

Consider number 17. You know that

17=9+8.

Then for negative numbers you have the same rule (with respect to sign -):

-17=(-9)+(-8).

Since (-9)+9=9+(-9)=9-9=0, you have that

-17+9=(-9)+(-8)+9=(-9+9)+(-8)=0+(-8)=-8.

Answer: -17=(-9)+(-8).

5 0
3 years ago
4/x - 3/y = 1 ; 6/x + 15/y = 8 solve this equation​
Soloha48 [4]

Answer:

x=2

y=3

Solution:

First we find common denominators. It is "xy". Then we multiply numerators by common denominator. We get followings:

(4y-3x)/xy=1; (6y+15x)/xy=8

Then

4y-3x=xy;

6y+15=8xy

Multiply first equasion by 5

20y-15x=5xy

Now we add two equasions to get one

20y-15x=5xy

6y+15x=8xy

We get

26y=13xy

Cut "y" and we will find "x"

26=13x

x=2

Put x value into the first equasion(4y-3x=xy) to find out "y"

4y-6=2y

2y=6

y=3

4 0
3 years ago
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
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