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sergey [27]
3 years ago
11

4/x - 3/y = 1 ; 6/x + 15/y = 8 solve this equation​

Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

x=2

y=3

Solution:

First we find common denominators. It is "xy". Then we multiply numerators by common denominator. We get followings:

(4y-3x)/xy=1; (6y+15x)/xy=8

Then

4y-3x=xy;

6y+15=8xy

Multiply first equasion by 5

20y-15x=5xy

Now we add two equasions to get one

20y-15x=5xy

6y+15x=8xy

We get

26y=13xy

Cut "y" and we will find "x"

26=13x

x=2

Put x value into the first equasion(4y-3x=xy) to find out "y"

4y-6=2y

2y=6

y=3

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Let's simplify step-by-step.

5x^3 + 3 + 2x^3 − x^2 + 1

= 5x^3 + 3 + 2x^3 + −x^2 + 1

Combine Like Terms:

= 5x^3 + 3 + 2x^3 + −x^2 + 1

= ( 5x^3 + 2x^3 ) + ( −x^2 ) + ( 3 + 1 )

= 7x^3 + −x^2 + 4

Answer:

= 7x^3 − x^2 + 4

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5 0
3 years ago
Write the set of real numbers x less than 6 in set builder notation
maksim [4K]

Answer:

{x ∈ R: x<6}

Step-by-step explanation:

Given

  • x is a real number
  • x is less than 6

Required

Write the set using set builder notation

The very first thing to do is to list out the range of x, using inequalities;

x is less than 6 implies that -infiniti < x < 6

The next step is to translate this to set builder. This is done as follows

x ∈ R - > This means that x is a real number

x < 6 -> where x is less than 6.

Bringing these two together, it gives:

{x ∈ R: x<6}

Hence, the set of real numbers x less than 6 is equivalent to {x ∈ R: x<6} using set builder notation

6 0
3 years ago
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Snezhnost [94]

The answer is D. 42

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2 years ago
Read 2 more answers
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
2 years ago
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