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posledela
3 years ago
6

Math question ,how ?

Mathematics
2 answers:
Troyanec [42]3 years ago
8 0
Let x be height of the shadow
30/15 = 90/x
Do cross multiplication
30x =1350
x = 45

Let h= height of the screen
1/4 of 45 is 11.25
H = 11.25 + 45
H= 56.25

There's your answer. I hope I did it right.
Scorpion4ik [409]3 years ago
6 0
Height of the screen = x
height of the shadow = \frac{3}{4}x

ΔAEC ∼ ΔADB  ⇒

\frac{BD}{AB}= \frac{CE}{AC} \\  \\    \frac{15}{30}= \frac{ \frac{3}{4}x }{90+30} \\ \\  \frac{1}{2}= \frac{ \frac{3}{4}x }{120} \\ \\  \frac{3}{4}x = \frac{120*1}{2}=60 \\  \\ x=60: \frac{3}{4}=60* \frac{4}{3}=20*4=80 \ cm

Height of the screen is 80 cm.

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Given: A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles.

Total marbles other than green = 8

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7 0
3 years ago
find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS
charle [14.2K]

Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

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