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Rasek [7]
4 years ago
14

What is the equation of line l?

Mathematics
1 answer:
inessss [21]4 years ago
5 0
Y=-3/2L -2. At the Y axis, line L is at -2, so we add that as B or the Y intercept. We can see that the graph goes 2 over to the right and down three, which makes the slope negative and 3/2 (rise/run)
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A multinational firm wants to estimate the average number of hours in a month that theiremployees spend on social media while on
elena55 [62]

Answer:

95% of the population spent between 16.8 hours to 26.2 hours on social media per month

Step-by-step explanation:

  1. subtracting 1 from sample size: 83-1= 82
  2. Note Mean=21.5 and standard deviation=2.5
  3. Subtracting confidence interval from 1 and dividing by 2: (1-0.95)/2=0.025
  4. At α=0.025 and dF=82,  the t-distribution table gives  1.984
  5. Divide standard deviation by square root of sample size: 21.5/√83= 2.36
  6. Multiplying answer in step 4 by answer in step 5: 2.36×1.984= 4.68
  7. For lower end: 21.5-4.68= 16.82
  8. for upper end: 21.5+4.68=26.18

7 0
4 years ago
Read 2 more answers
Complete the proof by providing the missing statement and reasons
Lisa [10]

Answer:

In triangle SHD and triangle STD.

\overline{SD} \perp \overline{HT}          [Side]

Since, a line is said to be perpendicular to another line if the two lines intersect at a right angle.

⇒ \angle SDH = \angle SDT = 90^{\circ}

\overline{SH} \cong \overline{ST}       [leg]               [Given]

Reflexive property states that the value is equal to itself.

\overline{SD} \cong \overline{SD}       [Leg]       [Reflexive property]

HL(Hypotenuse-leg) theorem states that any two right triangles that have a congruent hypotenuse and a corresponding congruent leg are the congruent triangles.


then, by HL theorem;

\triangle SHD \cong \triangle STD                       Proved!



6 0
3 years ago
A triangle is placed in a semicircle with a radius of 3 yd, as shown below. Find the area of the shaded region.
Kitty [74]

Answer:

Considering that the shaded area is the part of the semi circle outside the triangle:

Area of circle= Pi x radius2 (this means radius squared)

Area of triangle= 1/2 x base x height

1/2 (because it is a semi circle) x 3.14 (in replacement of pi as directed by question) x 9squared= 127.17

127.17 - (1/2 x 18 x 9) = 46.17cmsquared

3 0
3 years ago
What is the product of 567 and 8
Doss [256]
Answer:

4356

use a calculator
8 0
4 years ago
. -3(2x + 1) = 2(-3x - 1)
Marina CMI [18]
No solution to this problem
4 0
3 years ago
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