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Rasek [7]
4 years ago
14

What is the equation of line l?

Mathematics
1 answer:
inessss [21]4 years ago
5 0
Y=-3/2L -2. At the Y axis, line L is at -2, so we add that as B or the Y intercept. We can see that the graph goes 2 over to the right and down three, which makes the slope negative and 3/2 (rise/run)
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What is 5/11 minus negative 4/11
MA_775_DIABLO [31]

<u><em>Answer:  1/11 and 0.09=0.10</em></u>

Step-by-step explanation:

subtract by the numbers. subtract it's to take away one number from to another from the difference between the numbers.

5-4/11

5-4=1

=1/11

You can also round up to the nearest hundredths is 0.10.

Hope this helps!

Thanks!

Have a great day!

5 0
3 years ago
Read 2 more answers
Which is a right triangle?<br> 10, 13,8<br> 7, 9, 16<br> 4. 8. 12<br> 36, 27, 45
geniusboy [140]

Answer:

get a piece of graphing paper and count out the squares and then when you make the triangles you should have your answer.

Step-by-step explanation:

all i know is that it's not the third one hope this helps!

8 0
3 years ago
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Determine the value of x. <br><br> 1) 14.75<br> 2)15.25<br> 3)11.92<br> 4)18.56
Leto [7]
Opposite angles are supplementary, the sum is 180 degrees.
6x+10+81.5=180
Combine like terms:
6x+91.5=180
Subtract 91.5 to both sides:
6x=88.5
Divide 6 to both sides:
x=14.75
The answer is 1) 14.75
Hope this helped!
3 0
3 years ago
60% of what number is equal to 30?<br> A) 0.5 B) 2 C) 18 D) 50
Arada [10]

Answer:

D. 50

Step-by-step explanation:

50/1 (60/100) =

3000/100 =

30/1 =

30

7 0
3 years ago
Read 2 more answers
here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa
lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

0.75k=5 \iff k=6.\bar{6}

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

0.25k=5 \iff k=20

So, there would be 20 bricks in a 5 feet tall stack.

Finally, a coin is about 0.006 feet, which leads to

0.006k=5 \iff k=833.\bar{3}

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0
3 years ago
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