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mr Goodwill [35]

3 years ago

8

Oscar wants to find the decimal equivalent of 4/11, so he divides. Study Oscar’s work shown here, and then answer the questions

below.

1 answer:

allsm [11]3 years ago

4 0

0.36363636363636363 repeatedly

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Use the substitution method to find the solution for the system of equations. Write the answer as an ordered pair. 3x+2y=23 (1/2

mario62 [17]

Answer:

x = 7.75 y = -0.125

Step-by-step explanation:

3x + 2y = 23 1/2x - y = 4

2(1/2x - y) = (4)2 1x - 2y = 8

3x + 2y = 23

+ 1x - 2y = 8

4x = 31

x = 7.75

3(7.75) + 2y = 23

23.25 + 2y = 23

2y = -0.25

y = -0.125

8 0

3 years ago

Lynn takes out a loan for $7540 that charges an annual simple interest rate of 6.5%. She does not make any payments for 2 1/2 ye

sp2606 [1]

Answer:

8765.25

Step-by-step explanation:

p=$7540

r=6.5%

t=2.5

simple interest formula= (p*r*t)/100

(7540*6.5*2.5)/100=1225.25

total amount= p+S.I

=7540+1225.25

=8765.25

thankyou^^

7 0

3 years ago

Point Q is the midpoint of GH. GQ=2x+3, and GH=5x−5 .

olasank [31]

Since point Q is the midpoint of GH, that means that GH-GQ=HQ=GQ (since Q is the midpoint). Plugging them in, we get 5x-5-(2x+3)=3x-8=GQ=HQ. Since Q is the midpoint, that means that 3x-8=2x+3=GQ=HQ. Subtracting 2x from both sides as well as adding 8, we get that x=11 and 2(11)+3=25=GQ by plugging x into 2x+3

7 0

3 years ago

Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200

-Dominant- [34]

Answer:

1348 light years.

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.

$(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)$

Upon substituting our given values in above formula we will get,

$x^2=1200^2+1700^2-2*1200*1700*cos (52^o)$

$x^2=1440000+2890000-4080000*0.615661475$

$x^2=4330000-2511898.81933008$

$x^2=1818101.18066992$

Let us take square root of both sides of our equation.

$x=\sqrt{1818101.18066992}$

$x=1348.3698234\approx 1348$

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0

3 years ago

Aiden borrows a book from a public library. He read a few pages on day one. On day two, he reads twice the number of pages than

Thepotemich [5.8K]

Answer:

.

Step-by-step explanation:

6 0

3 years ago