First we need to arrange the numbers in this number set from smallest to biggest:17,18,24,27,31,39,42,47,55,65. Then there are 10 numbers in this number set. So when we calculate the median, we need to find the middle two numbers and calculate their average. So the median is (31+39)/2=35. SO the answer is B
Answer:
The 95% confidence interval is 
A 95% level of confidence mean that there is 95% chance that the true population mean will be in this interval
Step-by-step explanation:
From the question we are told that
The sample size is 
The mean is 
The standard deviation is 
Given that the confidence level is 95% then the level of significance is mathematically represented as

=> 
=> 
Next we obtain the critical value of
from the normal distribution table , the value is

Generally the margin of error is mathematically represented as

substituting values


The 95% level of confidence interval is mathematically represented as

substituting values


The 95% level of confidence mean that there is 95% chance that the true population mean will be in this interval
I found that the given prices are $ 4 per pack of pens and $ 3 per pack of penciles.
The question is how much the bookstore spent on pens.
Then you have to multiply the number packs of pens, which is 1,528, times the price per pack pens which is $ 4.
So, the answer is: 1528 packs of pens * $ 4 / pack of pens = $6112.