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Simora [160]
4 years ago
7

What is the following is the solution to the equation 25^(z+2) = 125

Mathematics
1 answer:
maksim [4K]4 years ago
3 0

First, rewrite the equation 25^{z+2} = 125 with the base equal to 5. Note that:

  • 25=5^2;
  • 125=5^3;
  • 25^{z+2}=(5^2)^{z+2}=5^{2\cdot (z+2)}.

Then

5^{2\cdot (z+2)}=5^3.

Since the bases are equal, you have that powers are equal too:

2\cdot (z+2)=3,\\ \\2z+4=3,\\ \\2z=3-4,\\ \\2z=-1,\\ \\z=-\dfrac{1}{2}.

Answer: z=-\dfrac{1}{2}.


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Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Masteriza [31]
Part A)

f(x) = 5^x
f(0) = 5^0
f(0) = 1
----------
f(x) = 5^x
f(1) = 5^1
f(1) = 5
----------
f(x) = 5^x
f(2) = 5^2
f(2) = 5*5
f(2) = 25
----------
f(x) = 5^x
f(3) = 5^3
f(3) = 5*5*5
f(3) = 125

-------------------

Rate of change for section A = (f(1) - f(0))/(1 - 0)
Rate of change for section A = (5 - 1)/(1 - 0)
Rate of change for section A = 4/1
Rate of change for section A = 4

Rate of change for section B = (f(3) - f(2))/(3 - 2)
Rate of change for section B = (125 - 25)/(3 - 2)
Rate of change for section B = 100/1
Rate of change for section B = 100

================================================

Part B)

From part A) above, we found,

Rate of change for section A = 4
Rate of change for section B = 100

Which means that section B's rate of change is 25 times greater (since 100/4 = 25, or 25*4 = 100)

Answer for part B: 25

================================================

Extra:  Explain why one rate of change is greater than the other.

The rate of change for section B is larger because the exponential function is growing faster as x increases. This is shown visually by the sharper and steeper incline as the function curve goes upward. The function starts off with relatively slower growth but it accelerates in speed. 

6 0
3 years ago
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