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Montano1993 [528]
3 years ago
5

Please help me find the pythagoras and missing letters. Statement and reason method. Will mark as brainliest

Mathematics
1 answer:
Brut [27]3 years ago
4 0

Answer:

Step-by-step explanation:

Lets begin with 5x.  The opposite sides of a rectangle are parallel, so 5x = 50 and x = 10

Then do the same for y.  3y = 27 so y = 9

2n + n = 90

3n = 90

n = 30

The corner = 90º

m = 90 - 10

m = 80º

Hopefully this helps.

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5x^2-2x=2<br>help plsmmm​
Yuki888 [10]

Answer:

Presumably you're solving for x here?  Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\

let's solve it.  First we'll multiply both sides by five, making the first term a perfect square:

25x^2 - 10x - 10 = 0\\

Now we'll add 11 to both sides:

25x^2 - 10x + 1 = 11\\

Which makes the left side a perfect square:

(5x - 1)^2 = 11

And now we can solve for x:

(5x - 1)^2 = 11\\\\5x - 1 =  \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86             x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46

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