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ch4aika [34]
3 years ago
12

Find the value of y if x equals 20? -2x+4y=-4

Mathematics
2 answers:
sammy [17]3 years ago
4 0

x=20

-2(20) + 4(y) =-4

-40+4y=-4

-4y=-36

y=9



Digiron [165]3 years ago
3 0
Y= 9

-2(20)+4y=-4
-40+4y=-4
-36=-4y
9=y
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PIT_PIT [208]
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pls solve quickly!: It took a boat 2 hours to reach town A going upstream. The way back was 1h20 min. What is the speed of the b
goldenfox [79]

Answer:

15 mph

Step-by-step explanation:

Given: Boat took 2 hours to reach Town A going upstream.

           Speed of stream= 3 mph

           Time taken to reach back home= 1 hours 20 minutes

Lets assume distance covered one side be "d" and speed of boat in still water be "s".

∴ Speed of boat in upstream= (s-3) \ mph

   Speed of boat in downstream= (s+3)\ mph

Also converting into fraction of time taken to reach back home.

Remember; 1 hour= 60 minutes

∴ Time taken to reach back home= 60+20= 80\ minutes

Converting time given into fraction= \frac{80\ minutes}{60\ minutes} = \frac{4}{3} \ hours

hence, Time taken to reach back home is \frac{4}{3} \ hours

Now forming equation of boat travelling upstream and downstream, considering distance remain constant.

We know, Distance= speed \times  time

⇒ (s-3)\times 2= (s+3)\times \frac{4}{3}

Using distributive property of multiplication

⇒2s-6= \frac{4}{3}s +4

subtracting both side by \frac{4}{3} s

⇒2s-\frac{4}{3} s-6= 4

Adding both side by 6

⇒ 2s-\frac{4}{3} s= 10

taking LCD as 3

⇒ \frac{2}{3} s= 10

Multiplying both side by \frac{3}{2}

⇒s= \frac{3}{2} \times 10

∴s= 15 mph

Hence, 15 mph is the speed of the boat in still water.

8 0
3 years ago
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NARA [144]

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Step-by-step explanation:

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8 0
3 years ago
Select from the drop-down menus to correctly complete the statements about the expression 5k+m3 .
Setler [38]

Answer:

sum

Step-by-step explanation:

4 0
2 years ago
Complete the work to find the dimensions of the rectangle. x(x – 3) = 10 x2 – 3x = 10 x2 – 3x – 10 = 10 – 10 (x + 2)(x – 5) = 0
Norma-Jean [14]

Answer:

Length =5

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Step-by-step explanation:

Given

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See comment for missing part of the question

Required

Complete the expression to determine the dimension of a rectangle

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x(x-3) =10

Open bracket

x^2 -3x = 10

Equate to 0

x^2 -3x - 10 =0

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x - 5 = 0 or x + 2 = 0

x = 5 or x = -2

The value of x cannot be negative

So:

x  = 5

Recall that:

Length = x

Width = x - 3

So:

Length =5

Width = 2 ---- i.e. 5 - 3

6 0
3 years ago
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