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kvv77 [185]
2 years ago
6

Combine like terms to simplify the expression below. 5y - 8x - y + 12y

Mathematics
1 answer:
sukhopar [10]2 years ago
5 0

Answer:

it will 16y-8x and common 8 is so 2y-x

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Solve the system of linear equations by elimination.<br> 5 - 2y = -8<br> 4x – 4y= 8
Alenkasestr [34]

Answer:

x = 17/2

y = 13/2

Step-by-step explanation:

Hope this helps!

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2 years ago
Write 5/z^-3 as a positive exponent
levacccp [35]

The correct answer will be 5z^3

8 0
3 years ago
The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

8 0
3 years ago
Is 4n-2 equivalent to 2(n-1)
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Answer:

no

Step-by-step explanation:

For example: 4(2)-2 and 2(2-1)

6 is not equal to 2

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2 years ago
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Step-by-step explanation:

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2 years ago
Read 2 more answers
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