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kvv77 [185]
3 years ago
6

Combine like terms to simplify the expression below. 5y - 8x - y + 12y

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0

Answer:

it will 16y-8x and common 8 is so 2y-x

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Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
olasank [31]

Answer:

x=18 y=69

Step-by-step explanation:

3x+5y=399

x+5y=363

2x=36

x=18

18+5y=363

5y=345

y=69

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2 years ago
Can someone answer this question please?
Keith_Richards [23]

Answer:b=2.5555555555...

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3 years ago
Is the number 935 a prime number yes or no
inysia [295]

Answer:

No

Step-by-step explanation:

This number has factors that are more than itself and one.

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3 years ago
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What are the steps to find <br> 40% of 200
denis-greek [22]
You just have to think what is 40% of 100 which is 40 then multiply 40 2 times to find out the answer four 40% of 200 when you do 40x2 it =80 so the answer is 80
8 0
3 years ago
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[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimens
MissTica

Answer:

  6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

  x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

  h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

  V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

  dV/dx = 0 = 27 -(3/4)x²

  x² = (4/3)(27) = 36

  x = 6

  h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

<em>Comment on maximum volume, minimum area</em>

In the general case of<em> an open-top box</em>, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a <em>closed top</em>, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

7 0
3 years ago
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