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Sidana [21]
3 years ago
8

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

b. \displaystyle 225y^2 + 150xy + 100x^2 = 225y^2 + 150xy + 100x^2

a. \displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2

Step-by-step explanation:

b. \displaystyle 225y^2 + 150xy + 100x^2 = 225y^2 + 150xy + 100x^2

a. \displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2

The two expressions are identical on each side of the equivalence symbol, therefore they are an identity.

I am joyous to assist you anytime.

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The diagram shows the curve with equation y = ( 1 + x ) cosx.
r-ruslan [8.4K]

Answer:

y = 1, 1.319, 1.024, 0

Step-by-step explanation:

Given equation:

y=(1+x)\cos x

\textsf{when}\:x=0:

\begin{aligned} \implies y & =(1+0)\cos 0\\\implies y & = 1\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{6}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{6}\right)\cos \left(\frac{\pi}{6}\right)\\\implies y & = 1.319\: \sf (3\:dp)\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{3}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{3}\right)\cos \left(\frac{\pi}{3}\right)\\\implies y & = 1.024\: \sf (3\:dp)\end{aligned}

\textsf{when}\:x=\dfrac{\pi}{2}:

\begin{aligned} \implies y & =\left(1+\frac{\pi}{2}\right)\cos \left(\frac{\pi}{2}\right)\\\implies y & = 0\end{aligned}

8 0
2 years ago
PLEASE HELP<br> I will give brainliest to right answer
choli [55]

Answer:

I'm pretty sure it is D because they're not super close to the line they're more spread out but I'm not rly sure

7 0
2 years ago
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Kenya has 2 hours to make a 104 mile trip. What rate must she average to make the trip in 2 hours? A) 50 mph B) 51 mph C) 52 mph
sattari [20]
C. 52 mph.
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8 0
3 years ago
4 times as much money as $5
lesantik [10]
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A winery has a vat with two pipes leading to it. The inlet pipe can fill the vat in 5 ​hours, while the outlet pipe can empty it
Rashid [163]

Answer:

                 time=40/3hours\approx 13.3hours

Step-by-step explanation:

The rates are additive: you can calculate the<em> inlet </em>rate and the <em>outlet</em> rate and add them algebraically, i.e. the inlet rate will be positive and the outlet rate will be negative.

<u>1. Inlet rate:</u>

1vat/5hours

<u />

<u>2. Outlet rate:</u>

1vat/8hours

<u>3. Net rate:</u>

            \text{Inlet rate - outlet rate}=1vat/5hours-1vat/8hours\\\\ \text{Net rate}=(8-5)vat/40hour=3vat/40hour=(3/40)vat/hour

<u>4. Time to fill the vat</u>

           rate=amount/time\implies time=amount/rate\\ \\ time=1vat/(3vat/40hour)

          time=40/3hours\approx 13.3hours

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3 years ago
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