Increase from 491,675 in the year 2000 to 782,341 in 2010.
A. The solution for the exponential growth rate, B. Write the exponential growth function and C What should the population be in 2016.
A. 782341/491675 = 1.5911750648294096710225250419484, or a growth rate of 59% over 10 years. So:(1+k)^10 = 1.5911750648294096710225250419484ln (1+k)^10 = ln 1.591175064829409671022525041948410 ln(1+k) = ln 1.5911750648294096710225250419484ln(1+k) = ln 1.5911750648294096710225250419484/10 = 0.04644727777645335179835425806392e^0.04644727777645335179835425806392 = 1+kk = 1.0475428488243655419718940009655, or 4.75428488243655419718940009655% growth rate per year.
B. Population year t = 491675 x (1.0475)^(t-2000)
C. Population in 2016 = 491675 x (1.0475)^16 = 1033100.64 people
Answer:
2,100
Step-by-step explanation:
$200 * 3.5= $700
$700 * 3= $2,100
Answer:
In the middle because half of 50 inches is 25 inches.
Step-by-step explanation:
Answer:
cubic meter of clay will be used to create all the pyramids
Step-by-step explanation:
The remaining part of the question is given in the attached file
Solution
The total clay used is equal to the sum of volumes of two triangular and three rectangular pyramids.
For Rectangular Pyramid,
Volume of three rectangular pyramids

Substituting the given values in above equation, we get -
cubic centimeter
For triangular Pyramid,
Volume of two triangular pyramids

cubic centimeter
Total clay used = Volume of 3 rectangular pyramid + volume of 2 triangular pyramid
Cubic centimeter
Answer:
Step-by-step explanation:
The first thing you ought to do is find out what you are trying to get. Desmos is an ideal program to do that if you don't have a graphing calculator. Just search for Desmos. It is pretty obvious once you get there. I've enclosed the graph to show you what it looks like.
Notice what happens around 5. The graph splits because effectively, you are dividing by 0 when you put 5 into the denominator. The question arises why doesn't the same thing happen at 0. It should: There is a discontinuity but it is very tiny. So the domain numbers that you should graph are
-1 0™ 1 2 3 4 4.5 4.8 5.3 5.4 6 7
™I wouldn't make 0 a part of this domain. But you can indicate with a dot where the graph goes.
I haven't filled in the range numbers. That's your job. All you have to do is fill in the table with points. Or you can put them on the graph that I have enclosed just to see where they points belong.
A graph is not to convey accuracy. It is to show the shape of function in question.